What is the integral of (\sqrt[9]{x}) ?

The integral of (\sqrt[9]{x}) is 9/10 x^{10/9}+C

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integral of (\sqrt[9]{x})

\frac{9}{10} x^{\frac{10}{9}} + C

Solution steps

Apply the Power Rule

: \frac{9}{10} x^{\frac{10}{9}}

= \frac{9}{10} x^{\frac{10}{9}}

Add a constant to the solution

= \frac{9}{10} x^{\frac{10}{9}} + C

\int 9 x^{- 3} d x

\frac{d}{d x} (\frac{2 x}{7 x ^{2} + 1})

y^{^{''}} + 256 y = sec (16 x)

y = 12 (x - \frac{1}{x})^{2}, at x = 2

y = 4 x cos (x^{2})

What is the integral of (\sqrt[9]{x}) ?
The integral of (\sqrt[9]{x}) is 9/10 x^{10/9}+C