What is the solution for y^'-ysin(x)=2sin(x) ?

The solution for y^'-ysin(x)=2sin(x) is y=e^{-cos(x)+c_{1}}-2

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y^'-ysin(x)=2sin(x)

y^{^{'}} - y sin (x) = 2 sin (x)

y = e^{- c o s (x) + c_{1}} - 2

Solution steps

y^{'} (x) - y sin (x) = 2 sin (x)

Solve separable ODE:

y = e^{- c o s (x) + c_{1}} - 2

y = e^{- c o s (x) + c_{1}} - 2

\frac{\partial}{\partial x} (sin (z^{3}) cos (x y))

\int \frac{x}{( x ^{2} + 4 x + 5 ) ^{2}} d x

x^{^{''}} + 3 x^{^{'}} + 4 x = 0

\frac{d}{d x} (x^{2} + y^{4})

f (x) = \frac{2 x - 1}{x + 7}, at x = 2

What is the solution for y^'-ysin(x)=2sin(x) ?
The solution for y^'-ysin(x)=2sin(x) is y=e^{-cos(x)+c_{1}}-2