What is the derivative of sin(e^{-2q}) ?

The derivative of sin(e^{-2q}) is -2e^{-2q}cos(e^{-2q})

What is the first derivative of sin(e^{-2q}) ?

The first derivative of sin(e^{-2q}) is -2e^{-2q}cos(e^{-2q})

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derivative of

sin (e^{- 2 q})

- 2 e^{- 2 q} cos (e^{- 2 q})

Solution steps

\frac{d}{d q} (sin (e^{- 2 q}))

Apply the chain rule:

cos (e^{- 2 q}) \frac{d}{d q} (e^{- 2 q})

= cos (e^{- 2 q}) \frac{d}{d q} (e^{- 2 q})

\frac{d}{d q} (e^{- 2 q}) = - 2 e^{- 2 q}

= cos (e^{- 2 q}) (- 2 e^{- 2 q})

Simplify

= - 2 e^{- 2 q} cos (e^{- 2 q})

\int (cos^{2} (2 x)) d x

\frac{\partial}{\partial y} (x^{2} y e^{x})

(0) (2.6)

n = 1 \sum \infty 4 (\frac{1}{4})^{n}

\frac{\partial}{\partial z} (z^{2} + x^{2})

What is the derivative of sin(e^{-2q}) ?
The derivative of sin(e^{-2q}) is -2e^{-2q}cos(e^{-2q})
What is the first derivative of sin(e^{-2q}) ?
The first derivative of sin(e^{-2q}) is -2e^{-2q}cos(e^{-2q})