What is the limit as x approaches 0 of arcsin(1+2x) ?

The limit as x approaches 0 of arcsin(1+2x) is pi/2

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limit as x approaches 0 of arcsin(1+2x)

x \to 0 lim (arcsin (1 + 2 x))

\frac{π}{2}

Decimal

1.57079 \dots

Solution steps

x \to 0 lim (arcsin (1 + 2 x))

Plug in the value

x = 0

= arcsin (1 + 2 \cdot 0)

Simplify

arcsin (1 + 2 \cdot 0) : \frac{π}{2}

= \frac{π}{2}

\int_{1}^{5} \frac{7}{x ^{2}} d x

\frac{d}{d x} ((5 x + 8)^{3})

\frac{d}{d x} ((\frac{x - 7}{x + 2})^{2})

x^{\frac{1}{3}}, 1000

y = (x^{x} + 1)^{2}

What is the limit as x approaches 0 of arcsin(1+2x) ?
The limit as x approaches 0 of arcsin(1+2x) is pi/2