What is the derivative of 4|x+3|-5 ?

The derivative of 4|x+3|-5 is (4(x+3))/(|x+3|)

What is the first derivative of 4|x+3|-5 ?

The first derivative of 4|x+3|-5 is (4(x+3))/(|x+3|)

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derivative of

4 ∣ x + 3 ∣ - 5

\frac{4 ( x + 3 )}{∣ x + 3 ∣}

Solution steps

\frac{d}{d x} (4 ∣ x + 3 ∣ - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 ∣ x + 3 ∣) - \frac{d}{d x} (5)

\frac{d}{d x} (4 ∣ x + 3 ∣) = \frac{4 ( x + 3 )}{∣ x + 3 ∣}

\frac{d}{d x} (5) = 0

= \frac{4 ( x + 3 )}{∣ x + 3 ∣} - 0

Simplify

= \frac{4 ( x + 3 )}{∣ x + 3 ∣}

f (x) = x e^{2 x}

x \to 1 lim (x^{3} - 4 x + 1)

x \to 0 lim ((x + 5) e^{\frac{1}{x}})

What is the derivative of 4|x+3|-5 ?
The derivative of 4|x+3|-5 is (4(x+3))/(|x+3|)
What is the first derivative of 4|x+3|-5 ?
The first derivative of 4|x+3|-5 is (4(x+3))/(|x+3|)