What is the derivative of x/(\sqrt[3]{x^2+4)} ?

The derivative of x/(\sqrt[3]{x^2+4)} is (3\sqrt[3]{x^2+4}(x^2+4)^{2/3}-2x^2)/(3(x^2+4)^{4/3)}

What is the first derivative of x/(\sqrt[3]{x^2+4)} ?

The first derivative of x/(\sqrt[3]{x^2+4)} is (3\sqrt[3]{x^2+4}(x^2+4)^{2/3}-2x^2)/(3(x^2+4)^{4/3)}

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derivative of

Solution steps

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

\frac{d x}{d x} = 1

Simplify

\int_{0}^{π} (8 e^{x} + 7 sin (x)) d x

\frac{5 x ^{2} + 3 x}{2 x}

y = (x^{3} - 25 x)^{14}, (- 5, 0)

n = 0 \sum \infty \frac{1}{( n + 1 )}

n = 1 \sum \infty \frac{n !}{n 7 ^{n}}

What is the derivative of x/(\sqrt[3]{x^2+4)} ?
The derivative of x/(\sqrt[3]{x^2+4)} is (3\sqrt[3]{x^2+4}(x^2+4)^{2/3}-2x^2)/(3(x^2+4)^{4/3)}
What is the first derivative of x/(\sqrt[3]{x^2+4)} ?
The first derivative of x/(\sqrt[3]{x^2+4)} is (3\sqrt[3]{x^2+4}(x^2+4)^{2/3}-2x^2)/(3(x^2+4)^{4/3)}