What is the tangent of y=2x^3-x^2+9,(2,21) ?

The tangent of y=2x^3-x^2+9,(2,21) is y=20x-19

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tangent of y=2x^3-x^2+9,(2,21)

tangent of

y = 2 x^{3} - x^{2} + 9, (2, 21)

y = 20 x - 19

Solution steps

Find the slope of

y = 2 x^{3} - x^{2} + 9 : \frac{d y}{d x} = 6 x^{2} - 2 x

Compute the slope of

y = 2 x^{3} - x^{2} + 9

(2, 21) : m = 20

Find the line with slope m=

20

and passing through

(2, 21) : y = 20 x - 19

y = 20 x - 19

\int \frac{1}{x - 4} d x

\frac{\partial}{\partial y} (x^{2} e^{5 x y})

y = - x^{2} - 2 x + 3, y = x^{2} - 1

- 2 (4 e^{- x^{2}} x^{3} - 6 e^{- x^{2}} x)

ln^{2} (2 x)

What is the tangent of y=2x^3-x^2+9,(2,21) ?
The tangent of y=2x^3-x^2+9,(2,21) is y=20x-19