What is laplacetransform e^{-t+7} ?

The answer to laplacetransform e^{-t+7} is (e^7)/(s+1)

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laplacetransform e^{-t+7}

laplace transform

e^{- t + 7}

\frac{e ^{7}}{s + 1}

Solution steps

L {e^{- t + 7}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= e^{7} L {e^{- t}}

L {e^{- t}} : \frac{1}{s + 1}

= e^{7} \frac{1}{s + 1}

Refine

e^{7} \frac{1}{s + 1} : \frac{e ^{7}}{s + 1}

= \frac{e ^{7}}{s + 1}

x^{^{''}} + \frac{1}{4} x^{^{'}} + 2 x = 0

\frac{- 5 s + 0.02}{s ^{2}}

y^{^{'}} - 2 \cdot x \cdot y = e^{x^{2}}

n = 0 \sum \infty 4^{\frac{1}{2 ^{n}}}

y = \frac{1}{x}, y = \frac{1}{x ^{2}}, y = 4

What is laplacetransform e^{-t+7} ?
The answer to laplacetransform e^{-t+7} is (e^7)/(s+1)