What is the integral of 2-1(e-x+2) ?

The integral of 2-1(e-x+2) is (x^2)/2-ex+C

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integral of 2-1(e-x+2)

\int 2 - 1 (e - x + 2) d x

\frac{x ^{2}}{2} - e x + C

Solution steps

\int 2 - 1 \cdot (e - x + 2) d x

Simplify

= \int x - e d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x - \int e d x

\int x d x = \frac{x ^{2}}{2}

\int e d x = e x

= \frac{x ^{2}}{2} - e x

Add a constant to the solution

= \frac{x ^{2}}{2} - e x + C

f (x) = 3 + 2 x^{3}

\frac{\partial}{\partial x} (2^{4 x} + 4 x^{2})

x^{2} - x y + 2 y - 2 = 0

\int an g cos (x) d x

\frac{13}{x + 1}