What is the integral of e^{ln(x^2)}x ?

The integral of e^{ln(x^2)}x is (x^4)/4+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{ln(x^2)}x

\int e^{l n (x^{2})} x d x

\frac{x ^{4}}{4} + C

Solution steps

\int e^{l n (x^{2})} x d x

Simplify

e^{l n (x^{2})} x : x^{3}

= \int x^{3} d x

Apply the Power Rule

: \frac{x ^{4}}{4}

= \frac{x ^{4}}{4}

Add a constant to the solution

= \frac{x ^{4}}{4} + C

\frac{d}{d x} (e^{2 x} - cos (2 x))

x \to 0 lim (\frac{( sin ( 4 x ) )}{x})

\int - 3 sin (5 x) cos^{2} (5 x) d x

x \to 0 lim (5 x)

f (x) = \frac{- 5}{x - 1}, at a = 8

What is the integral of e^{ln(x^2)}x ?
The integral of e^{ln(x^2)}x is (x^4)/4+C