What is (\partial)/(\partial x)(8xy^2) ?

The answer to (\partial)/(\partial x)(8xy^2) is 8y^2

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(\partial)/(\partial x)(8xy^2)

\frac{\partial}{\partial x} (8 x y^{2})

8 y^{2}

Solution steps

\frac{\partial}{\partial x} (8 x y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 y^{2} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= 8 y^{2} \cdot 1

Simplify

= 8 y^{2}

\int π (e^{- x})^{2} d x

x cos (\frac{y}{x}) \frac{d y}{d x} = y cos (\frac{y}{x}) - x

\frac{\partial}{\partial x} (\frac{2}{x ^{2}} + y)

- 4 x^{2} + x - 25, - 3 x^{2} + 17 x + 38

\frac{95 t}{99 t - 95}

What is (\partial)/(\partial x)(8xy^2) ?
The answer to (\partial)/(\partial x)(8xy^2) is 8y^2