What is the solution for (dy)/(dx)=-(2y^2)/(x^2) ?

The solution for (dy)/(dx)=-(2y^2)/(x^2) is y=-x/(2+c_{1)x}

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(dy)/(dx)=-(2y^2)/(x^2)

\frac{d y}{d x} = - \frac{2 y ^{2}}{x ^{2}}

y = - \frac{x}{2 + c _{1} x}

Solution steps

\frac{d y}{d x} = - \frac{2 y ^{2}}{x ^{2}}

Solve separable ODE:

y = - \frac{x}{2 + c _{1} x}

y = - \frac{x}{2 + c _{1} x}

(x + 4 x) (x^{\frac{3}{2}} - x)

y = ln ∣ sec (x) + tan (x) ∣

\frac{d}{d x} (\frac{4 sin ( x )}{3 + cos ( x )})

\frac{\partial}{\partial x} (x e^{- z})

\frac{\partial}{\partial x} (x^{2} ln (y))

What is the solution for (dy)/(dx)=-(2y^2)/(x^2) ?
The solution for (dy)/(dx)=-(2y^2)/(x^2) is y=-x/(2+c_{1)x}