What is the derivative of f(x)=8-x^3 ?

The derivative of f(x)=8-x^3 is -3x^2

What is the first derivative of f(x)=8-x^3 ?

The first derivative of f(x)=8-x^3 is -3x^2

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derivative of

f (x) = 8 - x^{3}

- 3 x^{2}

Solution steps

\frac{d}{d x} (8 - x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8) - \frac{d}{d x} (x^{3})

\frac{d}{d x} (8) = 0

\frac{d}{d x} (x^{3}) = 3 x^{2}

= 0 - 3 x^{2}

Simplify

= - 3 x^{2}

cos (x^{- 7})

y^{^{'}} = \frac{3 x + 2 y}{3 x + 2 y + 2}

y d y = \frac{2 x}{( 1 + x ^{2} )} d x, y (0) = 2

\frac{\partial}{\partial y} (3 x^{3 y})

\int (5 x - 4)^{2} d x

What is the derivative of f(x)=8-x^3 ?
The derivative of f(x)=8-x^3 is -3x^2
What is the first derivative of f(x)=8-x^3 ?
The first derivative of f(x)=8-x^3 is -3x^2