What is (\partial)/(\partial x)((x^2+y^2)/(xy)) ?

The answer to (\partial)/(\partial x)((x^2+y^2)/(xy)) is (x^2-y^2)/(x^2y)

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(\partial)/(\partial x)((x^2+y^2)/(xy))

\frac{\partial}{\partial x} (\frac{x ^{2} + y ^{2}}{x y})

\frac{x ^{2} - y ^{2}}{x ^{2} y}

Solution steps

\frac{\partial}{\partial x} (\frac{x ^{2} + y ^{2}}{x y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{y} \frac{\partial}{\partial x} (\frac{x ^{2} + y ^{2}}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{y} \cdot \frac{\frac{\partial}{\partial x} ( x ^{2} + y ^{2} ) x - \frac{\partial}{\partial x} ( x ) ( x ^{2} + y ^{2} )}{x ^{2}}

\frac{\partial}{\partial x} (x^{2} + y^{2}) = 2 x

\frac{\partial}{\partial x} (x) = 1

= \frac{1}{y} \cdot \frac{2 xx - 1 \cdot ( x ^{2} + y ^{2} )}{x ^{2}}

Simplify

\frac{1}{y} \cdot \frac{2 xx - 1 \cdot ( x ^{2} + y ^{2} )}{x ^{2}} : \frac{x ^{2} - y ^{2}}{x ^{2} y}

= \frac{x ^{2} - y ^{2}}{x ^{2} y}

\frac{\partial}{\partial x} (\frac{y ^{3}}{x})

\frac{d}{d x} (3 x^{2} + 4 x + 1)

\int \frac{1}{( x + 1 ) ( x + 3 )} d x

\int ((2 - x)^{\frac{1}{2}}) d x

f (x) = x^{4} ln (x)

What is (\partial)/(\partial x)((x^2+y^2)/(xy)) ?
The answer to (\partial)/(\partial x)((x^2+y^2)/(xy)) is (x^2-y^2)/(x^2y)