What is the derivative of f(x)=x^4ln(x) ?

The derivative of f(x)=x^4ln(x) is 4x^3ln(x)+x^3

What is the first derivative of f(x)=x^4ln(x) ?

The first derivative of f(x)=x^4ln(x) is 4x^3ln(x)+x^3

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derivative of

f (x) = x^{4} ln (x)

4 x^{3} ln (x) + x^{3}

Solution steps

\frac{d}{d x} (x^{4} ln (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{4}, g = ln (x)

= \frac{d}{d x} (x^{4}) ln (x) + \frac{d}{d x} (ln (x)) x^{4}

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 4 x^{3} ln (x) + \frac{1}{x} x^{4}

\frac{1}{x} x^{4} = x^{3}

= 4 x^{3} ln (x) + x^{3}

y = 7 x - x^{2} (1.6)

e^{x} - 2 x

\frac{d}{d x} (\frac{2 x ^{2} + 4 x + 6}{x})

\frac{d}{d x} (4 x^{2} - 4 x + 1)

f (x) = arcsin (ln (x))

What is the derivative of f(x)=x^4ln(x) ?
The derivative of f(x)=x^4ln(x) is 4x^3ln(x)+x^3
What is the first derivative of f(x)=x^4ln(x) ?
The first derivative of f(x)=x^4ln(x) is 4x^3ln(x)+x^3