What is the tangent of-3x^2,\at x=2 ?

The tangent of-3x^2,\at x=2 is y=-12x+12

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tangent of-3x^2,\at x=2

tangent of

- 3 x^{2}, at x = 2

y = - 12 x + 12

Solution steps

Find the tangent point:

(2, - 12)

Find the slope of

y = - 3 x^{2} : \frac{d y}{d x} = - 6 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 12

Find the line with slope m=

- 12

and passing through

(2, - 12) : y = - 12 x + 12

y = - 12 x + 12

\int (3 x + 5)^{2} d x

\frac{d}{d x} (x^{2} - 3 x - 5 x^{- 1} + 7 x^{- 2})

\frac{d y}{d x} = \frac{x ^{2} - 3}{6 y ^{2}}

\int_{0}^{1} \frac{x}{x + 1} d x

\int (2 t)^{- \frac{1}{2}} d t