What is the solution for (dy)/(dx)=(x^2-3)/(6y^2) ?

The solution for (dy)/(dx)=(x^2-3)/(6y^2) is y=\sqrt[3]{(x^3)/6-(3x)/2+c_{1}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=(x^2-3)/(6y^2)

\frac{d y}{d x} = \frac{x ^{2} - 3}{6 y ^{2}}

y = 3 \frac{x ^{3}}{6} - \frac{3 x}{2} + c_{1}

Solution steps

\frac{d y}{d x} = \frac{x ^{2} - 3}{6 y ^{2}}

Solve separable ODE:

y = 3 \frac{x ^{3}}{6} - \frac{3 x}{2} + c_{1}

y = 3 \frac{x ^{3}}{6} - \frac{3 x}{2} + c_{1}

\int_{0}^{1} \frac{x}{x + 1} d x

\int (2 t)^{- \frac{1}{2}} d t

\int_{- 2}^{s i n (x)} 3 t d t

\int_{0}^{1} \frac{2}{3} (x + 2 y) d x

\frac{d}{d x} (a x + cot (a x))

What is the solution for (dy)/(dx)=(x^2-3)/(6y^2) ?
The solution for (dy)/(dx)=(x^2-3)/(6y^2) is y=\sqrt[3]{(x^3)/6-(3x)/2+c_{1}}