What is (\partial)/(\partial x)(7ye^x) ?

The answer to (\partial)/(\partial x)(7ye^x) is 7ye^x

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(\partial)/(\partial x)(7ye^x)

\frac{\partial}{\partial x} (7 y e^{x})

7 y e^{x}

Solution steps

\frac{\partial}{\partial x} (7 y e^{x})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 y \frac{\partial}{\partial x} (e^{x})

Apply the common derivative:

\frac{\partial}{\partial x} (e^{x}) = e^{x}

= 7 y e^{x}

\frac{d y}{d x} = \frac{2 x + sec ^{2} ( x )}{2 y}, y (0) = - 7

\frac{d}{d x} (\frac{( 2 x ^{5} + 3 x ^{4} - x ^{3} + 2 )}{x ^{2}})

12 x^{2} - 12 x - 2

\int \frac{1}{1 + ( 1 + x ^{2} ) ^{\frac{1}{2}}} d x

\frac{d}{d x} (ln (x^{2} - 9))

What is (\partial)/(\partial x)(7ye^x) ?
The answer to (\partial)/(\partial x)(7ye^x) is 7ye^x