What is the derivative of (x^2-49)/(x-7) ?

The derivative of (x^2-49)/(x-7) is 1

What is the first derivative of (x^2-49)/(x-7) ?

The first derivative of (x^2-49)/(x-7) is 1

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derivative of

\frac{x ^{2} - 49}{x - 7}

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 49}{x - 7})

Simplify

\frac{x ^{2} - 49}{x - 7} : x + 7

= \frac{d}{d x} (x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (7)

\frac{d x}{d x} = 1

\frac{d}{d x} (7) = 0

= 1 + 0

Simplify

= 1

f (x) = 4 x - 3 x^{2}

(y - 2) d y + x d x = 0

y = x + 2, y = \frac{1}{x + 1}, [0, 2]

\frac{d}{d x} (5 x^{3} + 3 x)

\frac{\partial}{\partial x} (\frac{x ^{3} + 5}{y ^{3} - 1})

What is the derivative of (x^2-49)/(x-7) ?
The derivative of (x^2-49)/(x-7) is 1
What is the first derivative of (x^2-49)/(x-7) ?
The first derivative of (x^2-49)/(x-7) is 1