What is the integral of sec(x)tan(x)-4x ?

The integral of sec(x)tan(x)-4x is sec(x)-2x^2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of sec(x)tan(x)-4x

\int sec (x) tan (x) - 4 x d x

sec (x) - 2 x^{2} + C

Solution steps

\int sec (x) tan (x) - 4 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sec (x) tan (x) d x - \int 4 x d x

\int sec (x) tan (x) d x = sec (x)

\int 4 x d x = 2 x^{2}

= sec (x) - 2 x^{2}

Add a constant to the solution

= sec (x) - 2 x^{2} + C

\int (x^{4} + 5)^{3} x^{3} d x

\frac{d}{d x} (cos^{2} (x) sin^{2} (x))

\int 9 r cos (r) d r

y = x^{4 x}

\frac{d y}{d x} = (y^{2} - 4)

What is the integral of sec(x)tan(x)-4x ?
The integral of sec(x)tan(x)-4x is sec(x)-2x^2+C