What is the integral from 1 to 3 of 3/(x^2) ?

The integral from 1 to 3 of 3/(x^2) is 2

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integral from 1 to 3 of 3/(x^2)

\int_{1}^{3} \frac{3}{x ^{2}} d x

2

Solution steps

\int_{1}^{3} \frac{3}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{3} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{3}

= 3 [- \frac{1}{x}]_{1}^{3}

Compute the boundaries:

\frac{2}{3}

= 3 \cdot \frac{2}{3}

Simplify

= 2

\int \frac{x ^{4}}{( 3 - x ^{5} ) ^{2}} d x

\int 8 cos (2 x) d x

\int \frac{1}{( x - 6 ) ( x - 3 )} d x

\frac{\partial}{\partial x} (\frac{93}{2 + x ^{2} + y ^{2}})

x \to 1 lim (\frac{x}{∣ x ∣})

What is the integral from 1 to 3 of 3/(x^2) ?
The integral from 1 to 3 of 3/(x^2) is 2