What is (\partial)/(\partial y)(2xy^2+3x^2) ?

The answer to (\partial)/(\partial y)(2xy^2+3x^2) is 4xy

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(\partial)/(\partial y)(2xy^2+3x^2)

\frac{\partial}{\partial y} (2 x y^{2} + 3 x^{2})

4 x y

Solution steps

\frac{\partial}{\partial y} (2 x y^{2} + 3 x^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x y^{2}) + \frac{\partial}{\partial y} (3 x^{2})

\frac{\partial}{\partial y} (2 x y^{2}) = 4 x y

\frac{\partial}{\partial y} (3 x^{2}) = 0

= 4 x y + 0

Simplify

= 4 x y

f (x) = 8^{x}

(2 x - 3)^{3} (x^{4} + 1)^{2}

y^{^{''}} + b \cdot y = 0

\int_{1}^{2} \frac{6}{x ^{3} + 4 x} d x

x \to - 5 lim (\frac{2}{( x - 5 ) ^{3}})

What is (\partial)/(\partial y)(2xy^2+3x^2) ?
The answer to (\partial)/(\partial y)(2xy^2+3x^2) is 4xy