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Popular >

area y=2x^2+10,y=4x+16

Solution

area

y = 2 x^{2} + 10, y = 4 x + 16

Solution

\frac{64}{3}

+1

Decimal

21.33333 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{3} 2 x^{2} + 10 - (4 x + 16) d x

Solve

\int_{- 1}^{3} 2 x^{2} + 10 - (4 x + 16) d x : \frac{64}{3}

The area is:

= \frac{64}{3}

Graph

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Frequently Asked Questions (FAQ)

What is area y=2x^2+10,y=4x+16 ?
The answer to area y=2x^2+10,y=4x+16 is 64/3