What is (\partial)/(\partial x)(3x^2+2xy^3) ?

The answer to (\partial)/(\partial x)(3x^2+2xy^3) is 6x+2y^3

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(\partial)/(\partial x)(3x^2+2xy^3)

\frac{\partial}{\partial x} (3 x^{2} + 2 x y^{3})

6 x + 2 y^{3}

Solution steps

\frac{\partial}{\partial x} (3 x^{2} + 2 x y^{3})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) + \frac{\partial}{\partial x} (2 x y^{3})

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (2 x y^{3}) = 2 y^{3}

= 6 x + 2 y^{3}

\int ln (x - 9) d x

f (x) = 3 x^{4}, at x = - 2

\frac{8 x ^{2}}{4 - 3 x}

x^{2} - 4, - x^{2} + 4

\frac{d}{d x} ((3 x + 8) x^{2})

What is (\partial)/(\partial x)(3x^2+2xy^3) ?
The answer to (\partial)/(\partial x)(3x^2+2xy^3) is 6x+2y^3