What is expand b+x^2-kln(((x+1)(x-1))/k)-1 ?

The solution to expand b+x^2-kln(((x+1)(x-1))/k)-1 is b+x^2-kln((x^2-1)/k)-1

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expand b+x^2-kln(((x+1)(x-1))/k)-1

expand

b + x^{2} - k ln (\frac{( x + 1 ) ( x - 1 )}{k}) - 1

b + x^{2} - k ln (\frac{x ^{2} - 1}{k}) - 1

Solution steps

b + x^{2} - k ln (\frac{( x + 1 ) ( x - 1 )}{k}) - 1

\frac{( x + 1 ) ( x - 1 )}{k} = \frac{x ^{2} - 1}{k}

= b + x^{2} - k ln (\frac{x ^{2} - 1}{k}) - 1

\frac{2 x}{1 + x ^{2}}

\int \frac{x + 9}{2 x ^{3} - 18 x} d x

2 \frac{d y}{d x} + 18 y = 9

\int 5 sin^{2} (3 x) d x

\int_{0}^{1} \frac{1}{x ^{0.2}} d x

What is expand b+x^2-kln(((x+1)(x-1))/k)-1 ?
The solution to expand b+x^2-kln(((x+1)(x-1))/k)-1 is b+x^2-kln((x^2-1)/k)-1