What is the solution for y^{''}-4y^'+4y=0,y(0)=2,y^'(0)=7 ?

The solution for y^{''}-4y^'+4y=0,y(0)=2,y^'(0)=7 is y=2e^{2t}+3te^{2t}

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y^{''}-4y^'+4y=0,y(0)=2,y^'(0)=7

y^{^{''}} - 4 y^{^{'}} + 4 y = 0, y (0) = 2, y^{^{'}} (0) = 7

y = 2 e^{2 t} + 3 t e^{2 t}

Solution steps

y^{''} (t) - 4 y^{'} (t) + 4 y = 0

Solve linear ODE:

y = 2 e^{2 t} + 3 t e^{2 t}

y = 2 e^{2 t} + 3 t e^{2 t}

n = 0 \sum \infty 1 (- \frac{1}{3})^{n}

\int 56 x d x

x \to 0 lim (\frac{1}{x + 2} - \frac{1}{2})

y = 4 x^{- 3}

\frac{d}{d x} (3 x^{l n (x)})

What is the solution for y^{''}-4y^'+4y=0,y(0)=2,y^'(0)=7 ?
The solution for y^{''}-4y^'+4y=0,y(0)=2,y^'(0)=7 is y=2e^{2t}+3te^{2t}