What is the derivative of y=4x^{-3} ?

The derivative of y=4x^{-3} is -(12)/(x^4)

What is the first derivative of y=4x^{-3} ?

The first derivative of y=4x^{-3} is -(12)/(x^4)

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derivative of

y = 4 x^{- 3}

- \frac{12}{x ^{4}}

Solution steps

\frac{d}{d x} (4 x^{- 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 (- 3 x^{- 3 - 1})

Simplify

4 (- 3 x^{- 3 - 1}) : - \frac{12}{x ^{4}}

= - \frac{12}{x ^{4}}

\frac{d}{d x} (3 x^{l n (x)})

(x, y) \to (- 1, 1) lim (x + y)

\int_{0}^{1} \frac{x ^{3}}{1 + x ^{3}} d x

\frac{d}{d t} (- 2 cos (t))

y^{^{''}} = - a y

What is the derivative of y=4x^{-3} ?
The derivative of y=4x^{-3} is -(12)/(x^4)
What is the first derivative of y=4x^{-3} ?
The first derivative of y=4x^{-3} is -(12)/(x^4)