What is the d/(dt)(-2cos(t)) ?

The d/(dt)(-2cos(t)) is 2sin(t)

What is the first d/(dt)(-2cos(t)) ?

The first d/(dt)(-2cos(t)) is 2sin(t)

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\frac{d}{d t} (- 2 cos (t))

2 sin (t)

Solution steps

\frac{d}{d t} (- 2 cos (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d t} (cos (t))

Apply the common derivative:

\frac{d}{d t} (cos (t)) = - sin (t)

= - 2 (- sin (t))

Simplify

= 2 sin (t)

y^{^{''}} = - a y

\frac{d}{d x} (- 2 cos (- 3 x + 7))

\int e^{2 x + 7} d x

\int (2 - x)^{\frac{1}{2}} d x

x \to 5 lim (6 x - 4)