What is the tangent of f(x)=5xcos(x),\at x=pi ?

The tangent of f(x)=5xcos(x),\at x=pi is y=-5x

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tangent of f(x)=5xcos(x),\at x=pi

tangent of

f (x) = 5 x cos (x), at x = π

y = - 5 x

Solution steps

Find the tangent point:

(π, - 5 π)

Find the slope of

f (x) = 5 x cos (x) : \frac{df ( x )}{d x} = 5 (cos (x) - x sin (x))

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 5

Find the line with slope m=

- 5

and passing through

(π, - 5 π) : y = - 5 x

y = - 5 x

f (x) = (x^{x} + 1)^{2}

\frac{d}{d x} ((2 x - 1) (x^{2} - 6 x + 3))

\frac{d y}{d t} = \frac{1}{1 + y}

\int 1 + sin (2 x) d x

f (x) = x^{2}, at x = 7

What is the tangent of f(x)=5xcos(x),\at x=pi ?
The tangent of f(x)=5xcos(x),\at x=pi is y=-5x