What is the solution for (dy)/(dt)= 1/(1+y) ?

The solution for (dy)/(dt)= 1/(1+y) is y=-1+sqrt(2(t+c_{1))+1},y=-sqrt(2(t+c_{1))+1}-1

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(dy)/(dt)= 1/(1+y)

\frac{d y}{d t} = \frac{1}{1 + y}

y = - 1 + 2 (t + c_{1}) + 1, y = - 2 (t + c_{1}) + 1 - 1

Solution steps

\frac{d y}{d t} = \frac{1}{1 + y}

Solve separable ODE:

y = - 1 + 2 (t + c_{1}) + 1, y = - 2 (t + c_{1}) + 1 - 1

y = - 1 + 2 (t + c_{1}) + 1, y = - 2 (t + c_{1}) + 1 - 1

\int 1 + sin (2 x) d x

f (x) = x^{2}, at x = 7

y^{^{''}} + 3 y^{^{'}} + 9 y = 0

h \to 6 lim (\frac{4 h}{h - 6})

\frac{d}{d x} (- tan (9 x))

What is the solution for (dy)/(dt)= 1/(1+y) ?
The solution for (dy)/(dt)= 1/(1+y) is y=-1+sqrt(2(t+c_{1))+1},y=-sqrt(2(t+c_{1))+1}-1