What is the derivative of-tan(9x) ?

The derivative of-tan(9x) is -sec^2(9x)*9

What is the first derivative of-tan(9x) ?

The first derivative of-tan(9x) is -sec^2(9x)*9

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\frac{d}{d x} (- tan (9 x))

- sec^{2} (9 x) \cdot 9

Solution steps

\frac{d}{d x} (- tan (9 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (tan (9 x))

Apply the chain rule:

sec^{2} (9 x) \frac{d}{d x} (9 x)

= sec^{2} (9 x) \frac{d}{d x} (9 x)

\frac{d}{d x} (9 x) = 9

= - sec^{2} (9 x) \cdot 9

x \to 0 lim ([(2 x + 1) (x - 3)])

y = 2 x + \frac{5}{x}

f (x) = ln (2 x), y = 0, y = 2

x \to 9 - lim (c a + 2)

\int 3 x + 6 d x

What is the derivative of-tan(9x) ?
The derivative of-tan(9x) is -sec^2(9x)*9
What is the first derivative of-tan(9x) ?
The first derivative of-tan(9x) is -sec^2(9x)*9