What is area f(x)=ln(2x),y=0,y=2 ?

The answer to area f(x)=ln(2x),y=0,y=2 is No Solution

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area f(x)=ln(2x),y=0,y=2

area

f (x) = ln (2 x), y = 0, y = 2

No Solution

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

0 = 2 :

False

0 = ln (2 x) : x = \frac{1}{2}

2 = ln (2 x) : x = \frac{e ^{2}}{2}

Curves not bounded

= No Solution

x \to 9 - lim (c a + 2)

\int 3 x + 6 d x

\int y^{2} (4 - y^{3})^{\frac{2}{3}} d y

\frac{\partial}{\partial x} (x^{2} \frac{y}{x ^{4} + y ^{2}})

x^{4} + x^{3}, x^{4} + x^{2} + 6 x

What is area f(x)=ln(2x),y=0,y=2 ?
The answer to area f(x)=ln(2x),y=0,y=2 is No Solution