What is area x^4+x^3,x^4+x^2+6x ?

The answer to area x^4+x^3,x^4+x^2+6x is 253/12

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area x^4+x^3,x^4+x^2+6x

area

x^{4} + x^{3}, x^{4} + x^{2} + 6 x

\frac{253}{12}

Decimal

21.08333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{3} x^{4} + x^{3} - (x^{4} + x^{2} + 6 x) d x

Solve

\int_{- 2}^{3} x^{4} + x^{3} - (x^{4} + x^{2} + 6 x) d x : \frac{253}{12}

The area is:

= \frac{253}{12}

y^{^{''}} - 3 y^{^{'}} + 2 y = 0, y (0) = 0, y^{^{'}} (0) = 0

cos (x), \frac{π}{3}

\int \frac{3 x - 1}{x ^{2} - 1} d x

\frac{d}{d x} (\frac{9 - x ^{2}}{8 x})

n = 1 \sum \infty \frac{( x ^{n} )}{7 n}

What is area x^4+x^3,x^4+x^2+6x ?
The answer to area x^4+x^3,x^4+x^2+6x is 253/12