What is the integral from 1 to 4 of 1/(sqrt(x-1)) ?

The integral from 1 to 4 of 1/(sqrt(x-1)) is 2sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 4 of 1/(sqrt(x-1))

\int_{1}^{4} \frac{1}{x - 1} d x

23

Decimal

3.46410 \dots

Solution steps

\int_{1}^{4} \frac{1}{x - 1} d x

Apply u-substitution

: \int_{0}^{3} 2 d u

= \int_{0}^{3} 2 d u

Integral of a constant:

\int a d x = a x

= [2 u]_{0}^{3}

Compute the boundaries:

23

= 23

\int ln (1 - x) d x

\frac{d y}{d t} = 2 (t + 1) y, y (0) = 1

\frac{d}{d x} (e^{x} - x e^{x})

\int_{1}^{2} 3 r^{4} ln (r) d r

x \to 2 lim (6 x + 13)

What is the integral from 1 to 4 of 1/(sqrt(x-1)) ?
The integral from 1 to 4 of 1/(sqrt(x-1)) is 2sqrt(3)