What is area x^2-6x+9,x^2-x+6,[0,5] ?

The answer to area x^2-6x+9,x^2-x+6,[0,5] is 493/10

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area x^2-6x+9,x^2-x+6,[0,5]

area

x^{2} - 6 x + 9, x^{2} - x + 6, [0, 5]

\frac{493}{10}

Decimal

49.3

Solution steps

Apply the area formula:

\int_{0}^{5} x^{2} - 6 x + 9 - (x^{2} - x + 6) d x

Solve

\int_{0}^{5} x^{2} - 6 x + 9 - (x^{2} - x + 6) d x : \frac{493}{10}

The area is:

= \frac{493}{10}

t \frac{d y}{d t} = t^{3} + 6 t^{3} y

x \to 0 + lim (x (12))

\frac{\partial}{\partial y} (x + 2 x y - 3 y^{2})

\int_{a}^{3 a} x d x

x - 2, x, 0, 4

What is area x^2-6x+9,x^2-x+6,[0,5] ?
The answer to area x^2-6x+9,x^2-x+6,[0,5] is 493/10