What is the derivative of f(x)=x^3-3x+2 ?

The derivative of f(x)=x^3-3x+2 is 3x^2-3

What is the first derivative of f(x)=x^3-3x+2 ?

The first derivative of f(x)=x^3-3x+2 is 3x^2-3

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derivative of

f (x) = x^{3} - 3 x + 2

3 x^{2} - 3

Solution steps

\frac{d}{d x} (x^{3} - 3 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (2)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 3 x^{2} - 3 + 0

Simplify

= 3 x^{2} - 3

\frac{d}{d x} (\frac{1}{x ^{15}})

\frac{1}{14 x ^{2}}, x, \frac{x}{4}

\int x^{2} - x^{3} d x

\int_{0}^{1} \frac{1}{3 x} d x

\int_{0}^{25} (- 6 x) d x

What is the derivative of f(x)=x^3-3x+2 ?
The derivative of f(x)=x^3-3x+2 is 3x^2-3
What is the first derivative of f(x)=x^3-3x+2 ?
The first derivative of f(x)=x^3-3x+2 is 3x^2-3