What is (\partial)/(\partial x)(1/6 x^3) ?

The answer to (\partial)/(\partial x)(1/6 x^3) is (x^2)/2

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(\partial)/(\partial x)(1/6 x^3)

\frac{\partial}{\partial x} (\frac{1}{6} x^{3})

\frac{x ^{2}}{2}

Solution steps

\frac{\partial}{\partial x} (\frac{1}{6} x^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{6} \frac{\partial}{\partial x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{6} \cdot 3 x^{3 - 1}

Simplify

\frac{1}{6} \cdot 3 x^{3 - 1} : \frac{x ^{2}}{2}

= \frac{x ^{2}}{2}

f (x) = 2 x^{2} + 3 x - 2, (- 1, - 3)

\frac{d}{d x} (e^{x^{2} + x y})

\int \frac{1}{4 - x ^{2}} d x

9 x y^{^{'}} + y = 90 x

g (x) = x^{- \frac{5}{3}} - x + e^{40}

What is (\partial)/(\partial x)(1/6 x^3) ?
The answer to (\partial)/(\partial x)(1/6 x^3) is (x^2)/2