What is (\partial)/(\partial y)(3cos(x)-sin(x)y) ?

The answer to (\partial)/(\partial y)(3cos(x)-sin(x)y) is -sin(x)

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(\partial)/(\partial y)(3cos(x)-sin(x)y)

\frac{\partial}{\partial y} (3 cos (x) - sin (x) y)

- sin (x)

Solution steps

\frac{\partial}{\partial y} (3 cos (x) - sin (x) y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 cos (x)) - \frac{\partial}{\partial y} (sin (x) y)

\frac{\partial}{\partial y} (3 cos (x)) = 0

\frac{\partial}{\partial y} (sin (x) y) = sin (x)

= 0 - sin (x)

Simplify

= - sin (x)

y = (25 - 4 x^{2})^{2}, x = - \frac{5}{2}, x = \frac{5}{2}

\int \frac{5 x + 3}{x ^{2} + 1} d x

n = 1 \sum \infty 1 9^{n} x^{n} n!

x \to - 2 + lim (\frac{- 6 x}{x + 2})

\int \frac{x}{x ^{4} + 2 x ^{2} + 1} d x

What is (\partial)/(\partial y)(3cos(x)-sin(x)y) ?
The answer to (\partial)/(\partial y)(3cos(x)-sin(x)y) is -sin(x)