What is (\partial)/(\partial x)(4sin(xy)) ?

The answer to (\partial)/(\partial x)(4sin(xy)) is 4cos(xy)y

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(\partial)/(\partial x)(4sin(xy))

\frac{\partial}{\partial x} (4 sin (x y))

4 cos (x y) y

Solution steps

\frac{\partial}{\partial x} (4 sin (x y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{\partial}{\partial x} (sin (x y))

Apply the chain rule:

cos (x y) \frac{\partial}{\partial x} (x y)

= cos (x y) \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x y) = y

= 4 cos (x y) y

y = (\frac{2 x - 3}{( x ^{2} + 4 ) ^{2}})

(1, 4), (4, 1)

n = 0 \sum \infty \frac{( n ! ) ^{2}}{2 ^{n^{2}}}

y = (2 x + e^{- x^{2}})^{3}

\frac{d P}{d t} = P (a - b P)

What is (\partial)/(\partial x)(4sin(xy)) ?
The answer to (\partial)/(\partial x)(4sin(xy)) is 4cos(xy)y