What is (\partial)/(\partial y)(x^2sin(y)) ?

The answer to (\partial)/(\partial y)(x^2sin(y)) is x^2cos(y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(x^2sin(y))

\frac{\partial}{\partial y} (x^{2} sin (y))

x^{2} cos (y)

Solution steps

\frac{\partial}{\partial y} (x^{2} sin (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} \frac{\partial}{\partial y} (sin (y))

Apply the common derivative:

\frac{\partial}{\partial y} (sin (y)) = cos (y)

= x^{2} cos (y)

\frac{\partial}{\partial y} (2 e^{x})

\frac{d}{d t} (sec (t) tan (t))

\frac{d}{d x} (- 2 cot (x) + 3 csc (x))

y = 5 cos (x), y = 5 sin (x), 0 \leq x \leq π

\frac{d}{d x} ((x^{2} - 1)^{\frac{1}{3}})

What is (\partial)/(\partial y)(x^2sin(y)) ?
The answer to (\partial)/(\partial y)(x^2sin(y)) is x^2cos(y)