What is area y=5cos(x),y=5sin(x),0<= x<= pi ?

The answer to area y=5cos(x),y=5sin(x),0<= x<= pi is 10sqrt(2)

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area y=5cos(x),y=5sin(x),0<= x<= pi

area

y = 5 cos (x), y = 5 sin (x), 0 \leq x \leq π

102

Solution steps

Apply the area formula:

\int_{0}^{π} ∣ 5 cos (x) - 5 sin (x) ∣ d x

Solve

\int_{0}^{π} ∣ 5 cos (x) - 5 sin (x) ∣ d x : 102

The area is:

= 102

\frac{d}{d x} ((x^{2} - 1)^{\frac{1}{3}})

\int 0 sin (n x) d x

f (x) = 0.1 x^{3} - 0.45 x^{2} + 2.43 x + 300

\frac{d}{d x} (\frac{3}{x ^{2} - 4})

7 x sin (x^{2})

What is area y=5cos(x),y=5sin(x),0<= x<= pi ?
The answer to area y=5cos(x),y=5sin(x),0<= x<= pi is 10sqrt(2)