What is the derivative of 3/(x^2-4) ?

The derivative of 3/(x^2-4) is -(6x)/((x^2-4)^2)

What is the first derivative of 3/(x^2-4) ?

The first derivative of 3/(x^2-4) is -(6x)/((x^2-4)^2)

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\frac{d}{d x} (\frac{3}{x ^{2} - 4})

- \frac{6 x}{( x ^{2} - 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3}{x ^{2} - 4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{x ^{2} - 4})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((x^{2} - 4)^{- 1})

Apply the chain rule:

- \frac{1}{( x ^{2} - 4 ) ^{2}} \frac{d}{d x} (x^{2} - 4)

= - \frac{1}{( x ^{2} - 4 ) ^{2}} \frac{d}{d x} (x^{2} - 4)

\frac{d}{d x} (x^{2} - 4) = 2 x

= 3 (- \frac{1}{( x ^{2} - 4 ) ^{2}} \cdot 2 x)

Simplify

3 (- \frac{1}{( x ^{2} - 4 ) ^{2}} \cdot 2 x) : - \frac{6 x}{( x ^{2} - 4 ) ^{2}}

= - \frac{6 x}{( x ^{2} - 4 ) ^{2}}

7 x sin (x^{2})

\int - cos (x) + sin (x) + 4 d x

\int \frac{csc ^{2} ( x )}{cot ( x ) + 1} d x

f (x) = (2 + 5 x) (5 - 4 x), at x = 1

y^{^{'}} - y = 5.2

What is the derivative of 3/(x^2-4) ?
The derivative of 3/(x^2-4) is -(6x)/((x^2-4)^2)
What is the first derivative of 3/(x^2-4) ?
The first derivative of 3/(x^2-4) is -(6x)/((x^2-4)^2)