What is area y=sqrt(x^2-1),x=1,x=3 ?

The answer to area y=sqrt(x^2-1),x=1,x=3 is -1/2 ln(2sqrt(2)+3)+3sqrt(2)

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area y=sqrt(x^2-1),x=1,x=3

area

y = x^{2} - 1, x = 1, x = 3

- \frac{1}{2} ln (22 + 3) + 32

Solution steps

Apply the area formula:

\int_{1}^{3} x^{2} - 1 d x

Solve

\int_{1}^{3} x^{2} - 1 d x : - \frac{1}{2} ln (22 + 3) + 32

The area is:

= - \frac{1}{2} ln (22 + 3) + 32

\int 3 x ln (4 x) d x

f (x) = (3 - 5 x)^{9}

\frac{d}{d x} (cos^{2} ((a - x)^{3}))

t^{2} cos (8 t)

What is area y=sqrt(x^2-1),x=1,x=3 ?
The answer to area y=sqrt(x^2-1),x=1,x=3 is -1/2 ln(2sqrt(2)+3)+3sqrt(2)