What is the integral of 7\sqrt[4]{58-7x}-14 ?

The integral of 7\sqrt[4]{58-7x}-14 is -4/5 (58-7x)^{5/4}+2(58-7x)+C

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integral of 7\sqrt[4]{58-7x}-14

- \frac{4}{5} (58 - 7 x)^{\frac{5}{4}} + 2 (58 - 7 x) + C

Solution steps

Apply u-substitution

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int 2 d u = 2 u

= - \frac{4}{5} u^{\frac{5}{4}} + 2 u

Substitute back

u = 58 - 7 x

= - \frac{4}{5} (58 - 7 x)^{\frac{5}{4}} + 2 (58 - 7 x)

Add a constant to the solution

= - \frac{4}{5} (58 - 7 x)^{\frac{5}{4}} + 2 (58 - 7 x) + C

t^{2} cos (8 t)

\frac{d}{d x} (x^{3} - 8 x^{2} + 31 x)

\frac{d ^{2}}{d x ^{2}} (x^{2} e^{x})

n = 0 \sum \infty - 3^{n}

\frac{7}{x}

What is the integral of 7\sqrt[4]{58-7x}-14 ?
The integral of 7\sqrt[4]{58-7x}-14 is -4/5 (58-7x)^{5/4}+2(58-7x)+C