What is the derivative of x^3-8x^2+31x ?

The derivative of x^3-8x^2+31x is 3x^2-16x+31

What is the first derivative of x^3-8x^2+31x ?

The first derivative of x^3-8x^2+31x is 3x^2-16x+31

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\frac{d}{d x} (x^{3} - 8 x^{2} + 31 x)

3 x^{2} - 16 x + 31

Solution steps

\frac{d}{d x} (x^{3} - 8 x^{2} + 31 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (8 x^{2}) + \frac{d}{d x} (31 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (8 x^{2}) = 16 x

\frac{d}{d x} (31 x) = 31

= 3 x^{2} - 16 x + 31

\frac{d ^{2}}{d x ^{2}} (x^{2} e^{x})

n = 0 \sum \infty - 3^{n}

\frac{7}{x}

\int \frac{1}{- x ^{2} + 4 x - 1} d x

y = x^{2} - 12 x + 4

What is the derivative of x^3-8x^2+31x ?
The derivative of x^3-8x^2+31x is 3x^2-16x+31
What is the first derivative of x^3-8x^2+31x ?
The first derivative of x^3-8x^2+31x is 3x^2-16x+31