What is the tangent of y=x^2-12x+4 ?

The tangent of y=x^2-12x+4 is y=(2a_{0}-12)x-a_{0}^2+4

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tangent of y=x^2-12x+4

tangent of

y = x^{2} - 12 x + 4

y = (2 a_{0} - 12) x - a_{0}^{2} + 4

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{2} - 12 a_{0} + 4)

Find the slope of

y = x^{2} - 12 x + 4 : \frac{d y}{d x} = 2 x - 12

Compute the slope of

y = x^{2} - 12 x + 4

x = a_{0} : m = 2 a_{0} - 12

Find the line with slope m=

2 a_{0} - 12

and passing through

(a_{0}, a_{0}^{2} - 12 a_{0} + 4) : y = (2 a_{0} - 12) x - a_{0}^{2} + 4

y = (2 a_{0} - 12) x - a_{0}^{2} + 4

\int e^{t} sin (3 t) d t

2 tan^{2} (4 x)

\frac{\partial}{\partial x} (x^{2} y)

y = lo g_{3} (sin (x^{2}))

y^{^{'}} + 2 y = x y^{- 2}

What is the tangent of y=x^2-12x+4 ?
The tangent of y=x^2-12x+4 is y=(2a_{0}-12)x-a_{0}^2+4