What is the derivative of 2tan^2(4x) ?

The derivative of 2tan^2(4x) is 16sec^2(4x)tan(4x)

What is the first derivative of 2tan^2(4x) ?

The first derivative of 2tan^2(4x) is 16sec^2(4x)tan(4x)

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derivative of

2 tan^{2} (4 x)

16 sec^{2} (4 x) tan (4 x)

Solution steps

\frac{d}{d x} (2 tan^{2} (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (tan^{2} (4 x))

Apply the chain rule:

2 tan (4 x) \frac{d}{d x} (tan (4 x))

= 2 tan (4 x) \frac{d}{d x} (tan (4 x))

\frac{d}{d x} (tan (4 x)) = sec^{2} (4 x) \cdot 4

= 2 \cdot 2 tan (4 x) sec^{2} (4 x) \cdot 4

Simplify

= 16 sec^{2} (4 x) tan (4 x)

\frac{\partial}{\partial x} (x^{2} y)

y = lo g_{3} (sin (x^{2}))

y^{^{'}} + 2 y = x y^{- 2}

\frac{d}{d x} ((x - 1)^{2 x})

\frac{d}{d x} (10 arctan (x))

What is the derivative of 2tan^2(4x) ?
The derivative of 2tan^2(4x) is 16sec^2(4x)tan(4x)
What is the first derivative of 2tan^2(4x) ?
The first derivative of 2tan^2(4x) is 16sec^2(4x)tan(4x)