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Popular >

y^'=xy+x

Solution

y^{^{'}} = x y + x

Solution

y = e^{\frac{x ^{2}}{2} + c_{1}} - 1

Solution steps

y^{'} (x) = x y + x

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} + c_{1}} - 1

y = e^{\frac{x ^{2}}{2} + c_{1}} - 1

Graph

Popular Examples

\frac{d y}{d t} + 6 y = 0

integral from-1 to 1 of (2-2x^2)^2

\int_{- 1}^{1} (2 - 2 x^{2})^{2} d x

integral of tan^7(x)sec^5(x)

\int tan^{7} (x) sec^{5} (x) d x

y^{''}-3y^'+2y=4

y^{^{''}} - 3 y^{^{'}} + 2 y = 4

derivative of (4ln(x)/x)

\frac{d}{d x} (\frac{4 ln ( x )}{x})

Frequently Asked Questions (FAQ)

What is the solution for y^'=xy+x ?
The solution for y^'=xy+x is y=e^{(x^2)/2+c_{1}}-1