What is the derivative of (4ln(x)/x) ?

The derivative of (4ln(x)/x) is (4(1-ln(x)))/(x^2)

What is the first derivative of (4ln(x)/x) ?

The first derivative of (4ln(x)/x) is (4(1-ln(x)))/(x^2)

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\frac{d}{d x} (\frac{4 ln ( x )}{x})

\frac{4 ( 1 - ln ( x ) )}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{4 ln ( x )}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{ln ( x )}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 4 \cdot \frac{\frac{d}{d x} ( ln ( x ) ) x - \frac{d x}{d x} ln ( x )}{x ^{2}}

\frac{d}{d x} (ln (x)) = \frac{1}{x}

\frac{d x}{d x} = 1

= 4 \cdot \frac{\frac{1}{x} x - 1 \cdot ln ( x )}{x ^{2}}

Simplify

4 \cdot \frac{\frac{1}{x} x - 1 \cdot ln ( x )}{x ^{2}} : \frac{4 ( 1 - ln ( x ) )}{x ^{2}}

= \frac{4 ( 1 - ln ( x ) )}{x ^{2}}

\frac{\partial}{\partial x} (y - \frac{1}{x})

y^{^{'}} - y = 4 x

\frac{\partial}{\partial x} (arctan (x t))

y = x^{2} + 2

\frac{\partial}{\partial x} (4 y e^{4 x y})

What is the derivative of (4ln(x)/x) ?
The derivative of (4ln(x)/x) is (4(1-ln(x)))/(x^2)
What is the first derivative of (4ln(x)/x) ?
The first derivative of (4ln(x)/x) is (4(1-ln(x)))/(x^2)