What is the first derivative of x^2+9 ?

The first derivative of x^2+9 is 2x

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derivative of x^2+9

derivative of

x^{2} + 9

2 x

Solution steps

\frac{d}{d x} (x^{2} + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (9)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (9) = 0

= 2 x + 0

Simplify

= 2 x

n = 1 \sum \infty \frac{1}{9 n + 3 n - 2}

\frac{x + 7}{x - 7}

\frac{( 2 x + 1 )}{x ^{3}}

\int_{1}^{2} x^{2} + \frac{1}{4 x ^{2}} d x

f (x) = 1 - e^{- x}